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ddr_master0602
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Joined: 24 Mar 2005
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40.  Posted: Tue Nov 08, 2005 10:15 am Post subject: |
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i think that it is kinda neat, but you must really have a bunch of time on your hands to come up with all that geometry for the ddr arrow. with me i just draw it and if its a little off then oh well. like i said before it is kinda neat.
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sacratoy
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Joined: 23 Aug 2005
Location: Longmont, CO |
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munka
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Joined: 02 Oct 2004
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| 42. Posted: Tue Nov 08, 2005 2:11 pm Post subject: |
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and off of calculus/trig and back to geometry....
whats the area of the arrow if X = 1, 2 ,5????? 
whats the equasion for the area in terms of X???
it would be sometrhing like the big rectangle in the middle's area + the two sides + the middle piece... if u were to put the formulas in the same equasion (as long as parts don't overlap)
and now i think about it... big triangle minus 2 smaller triangles :\
this made sense in my head when i was writing it, so if it does not make sense... just read my mind k???  |
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dernalia
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Joined: 14 Jun 2005
Location: Earth |
| 43. Posted: Sun Nov 13, 2005 1:49 pm Post subject: |
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well, you know.. if you really wanted to... you could figure it out your self... =p
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killingscum
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Joined: 25 Oct 2005
Location: WHERE EVER DDR/ITG/PIU CALLS. |
| 44. Posted: Sun Nov 13, 2005 1:51 pm Post subject: |
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itg arrow, corners must be rounded.
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Zonic
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Joined: 07 Jun 2005
Location: & you want to know WHHHYYYY?? |
| 45. Posted: Sun Nov 13, 2005 2:05 pm Post subject: |
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| Advanced Math 8(grade) english, please....I just don't see how you can use this info except at a Konami trivia show..... |
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GARYYY
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Joined: 15 Jul 2005
Location: Traverse City, MI (USA) |
| 46. Posted: Sun Nov 13, 2005 6:12 pm Post subject: |
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| Quote: | dernalia wrote:
I made this at play practice yesturday
btw.. i missed the bottom segment length.. it should be:
(2(1/3)(1/4)(SquareRoot(2X^2)))
*All Expressions Anti Simplified for sake of those who don't as easily understand lowest terms
Because you can't figure that out without high school freshman geometry (or even earlier than that).
Hay /Chit-Chat, I was bored so I made this in my spare time, am I cool now?
Wherein the exponent is the optical depth along the tangent line of sight Z-sub-t, delta-gamma is the spectral width of channel N with band pass function psi (gamma), delta-omega is the angular field view of the instrument with response W(omega). The value of the exponent varies with the tangent height; effectively 0 at 100 km and generally increases downward. It's a combination of Rayleigh, aerosol, and gaseous species extinction. |
^^^yea, but thats not going to help in programming a arrow into a calculator 
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dernalia
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Joined: 14 Jun 2005
Location: Earth |
| 47. Posted: Sun Nov 13, 2005 9:36 pm Post subject: |
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yes, but you can find all the equations for graphing all the lines that make up the arrow.
all it is, is different modifcations of y=x of the form y=mx+b
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elementis0
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Joined: 01 Nov 2004
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| 48. Posted: Mon Nov 14, 2005 12:23 pm Post subject: |
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Lol and i thought my algebra class was hard
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sacratoy
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AA Bob
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Joined: 24 Aug 2005
Location: Alllll right! |
| 50. Posted: Mon Nov 14, 2005 7:31 pm Post subject: |
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| imfrodoâ¶â wrote: | | all of these are the diffrent slopes that i hope someone could use for me if they dont make sence when not written in normal form. the arrow would of coarse look quite wierd but i would like to see the program when you are done. |
Are you asking for someone to program their calculator to draw a DDR arrow? If so, I could do it fairly easily. However, I doubt you would be able to use it since you're probably a TI user (and I only use HP calcs...MUST...CONTROL...FANBOYISM). But if by some chance you have a 48/49 series HP calc, then yeah, I could program the arrow thing.
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dernalia
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Joined: 14 Jun 2005
Location: Earth |
| 51. Posted: Fri Nov 25, 2005 6:33 pm Post subject: |
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irecommend not using square roots in the equations for a ddr arrow... all you need are sinple linear equations
i had them earliar... i'll come up with some later if you don't feel like doing it yourself.. keep in mind that the middle horizontal line is being trisected.
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